x^2/2+3=35

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Solution for x^2/2+3=35 equation:



x^2/2+3=35
We move all terms to the left:
x^2/2+3-(35)=0
We add all the numbers together, and all the variables
x^2/2-32=0
We multiply all the terms by the denominator
x^2-32*2=0
We add all the numbers together, and all the variables
x^2-64=0
a = 1; b = 0; c = -64;
Δ = b2-4ac
Δ = 02-4·1·(-64)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16}{2*1}=\frac{-16}{2} =-8 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16}{2*1}=\frac{16}{2} =8 $

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